Solving Compound Inequalities: A Step-by-Step Guide

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Solving Compound Inequalities: A Step-by-Step Guide

Hey guys! Today, we're diving into the world of compound inequalities. If you've ever felt a little puzzled by those "or" and "and" statements in math problems, you're in the right place. We're going to break down how to solve a specific compound inequality step by step. So, let's get started and make those inequalities feel a whole lot less intimidating!

Understanding Compound Inequalities

Before we jump into solving, let's quickly define what compound inequalities are. Compound inequalities are essentially two inequalities joined together by either "or" or "and." This "or" and "and" is super important because it changes how we approach the problem and how we interpret the solution. Think of it like this: "and" means both conditions must be true at the same time, while "or" means at least one of the conditions needs to be true. So, the first key in tackling these problems is to identify whether you're dealing with an "or" or an "and" situation.

For instance, our example problem presents an "or" scenario: 4>βˆ’3x+34 > -3x + 3 or 9leβˆ’3x+29 le -3x + 2. This means we're looking for values of x that satisfy either the first inequality, the second inequality, or both. Keep this in mind as we work through the solution. Understanding this fundamental concept is crucial for correctly interpreting the final answer and graphing it on a number line, which we'll cover later.

Breaking Down the Problem: 4>βˆ’3x+34 > -3x + 3 or 9leβˆ’3x+29 le -3x + 2

Okay, let's tackle the compound inequality we have: 4>βˆ’3x+34 > -3x + 3 or 9leβˆ’3x+29 le -3x + 2. The best way to solve this is to treat it as two separate inequalities and solve each one individually. This makes the whole process much more manageable, and we can then combine the solutions at the end. So, we'll first focus on 4>βˆ’3x+34 > -3x + 3 and then move on to 9leβˆ’3x+29 le -3x + 2. Remember, we're using the properties of inequalities to isolate x in each case. That means we can add, subtract, multiply, or divide both sides of the inequality by the same number, but there's one golden rule: if we multiply or divide by a negative number, we need to flip the inequality sign. Keep this in mind, as it's a common place to make a mistake.

Solving the First Inequality: 4>βˆ’3x+34 > -3x + 3

Let's start with the first inequality: 4>βˆ’3x+34 > -3x + 3. Our goal here is to isolate x on one side of the inequality. The first step is to get rid of the constant term on the right side, which is +3. To do this, we'll subtract 3 from both sides of the inequality. This gives us:

4βˆ’3>βˆ’3x+3βˆ’34 - 3 > -3x + 3 - 3

Simplifying this, we get:

1>βˆ’3x1 > -3x

Now, we need to get x by itself. Notice that x is being multiplied by -3. To isolate x, we need to divide both sides of the inequality by -3. But remember that golden rule! Since we're dividing by a negative number, we must flip the inequality sign. So, we have:

1/βˆ’3<βˆ’3x/βˆ’31 / -3 < -3x / -3

This simplifies to:

βˆ’1/3<x-1/3 < x

We can also rewrite this as:

x>βˆ’1/3x > -1/3

So, the solution to our first inequality is x is greater than -1/3. Awesome! We're halfway there. Now, let's move on to the second inequality.

Solving the Second Inequality: 9leβˆ’3x+29 le -3x + 2

Now, let's tackle the second inequality: 9leβˆ’3x+29 le -3x + 2. Just like before, our aim is to isolate x. We'll start by subtracting 2 from both sides of the inequality to get rid of the constant term on the right side:

9βˆ’2leβˆ’3x+2βˆ’29 - 2 le -3x + 2 - 2

Simplifying this gives us:

7leβˆ’3x7 le -3x

Now, we need to get x by itself. Again, x is being multiplied by -3, so we'll divide both sides of the inequality by -3. And yes, you guessed it, we need to flip the inequality sign because we're dividing by a negative number. So, we have:

7/βˆ’3geβˆ’3x/βˆ’37 / -3 ge -3x / -3

This simplifies to:

βˆ’7/3gex-7/3 ge x

We can also rewrite this as:

xleβˆ’7/3x le -7/3

So, the solution to our second inequality is x is less than or equal to -7/3. Great! We've solved both inequalities separately. Now, comes the fun part: combining the solutions.

Combining the Solutions: "Or" Statements

Remember how we talked about the difference between "or" and "and"? Well, now it's time to put that knowledge to use. We have the solutions to our two inequalities:

  • x>βˆ’1/3x > -1/3
  • xleβˆ’7/3x le -7/3

Since our original problem used "or," we're looking for values of x that satisfy either inequality. This means our solution is simply the union of the two individual solutions. In other words, x can be greater than -1/3 or less than or equal to -7/3. There's no overlap needed like there would be with an "and" statement.

So, our combined solution is:

x>βˆ’1/3x > -1/3 or xleβˆ’7/3x le -7/3

This is our final answer! We've successfully solved the compound inequality. But, let's take it one step further and see how we can represent this solution graphically.

Graphing the Solution on a Number Line

Visualizing the solution on a number line can really help solidify your understanding. To graph our solution, we'll need a number line and to mark the key points: -7/3 and -1/3. Remember that -7/3 is approximately -2.33, so it's further to the left on the number line than -1/3, which is approximately -0.33.

Here's how we'll represent each part of the solution:

  • x>βˆ’1/3x > -1/3: Since x is strictly greater than -1/3, we'll use an open circle at -1/3 to indicate that -1/3 is not included in the solution. Then, we'll draw an arrow to the right, showing all values greater than -1/3 are part of the solution.
  • xleβˆ’7/3x le -7/3: Since x is less than or equal to -7/3, we'll use a closed circle at -7/3 to indicate that -7/3 is included in the solution. Then, we'll draw an arrow to the left, showing all values less than -7/3 are part of the solution.

When you put it all together, you'll have two arrows pointing in opposite directions, with an open circle at -1/3 and a closed circle at -7/3. This visual representation perfectly captures the solution to our compound inequality: all numbers less than or equal to -7/3 or greater than -1/3.

Key Takeaways and Common Mistakes

Let's recap some key takeaways from solving compound inequalities:

  • Identify "or" vs. "and": This is crucial for interpreting the solution correctly.
  • Solve Separately: Treat each inequality individually.
  • Flip the Sign: Remember to flip the inequality sign when multiplying or dividing by a negative number.
  • Combine Solutions: For "or," take the union of the solutions; for "and," find the intersection.
  • Graphing: Visualizing the solution on a number line is super helpful.

Now, let's talk about some common mistakes to watch out for:

  • Forgetting to Flip the Sign: This is the most common error. Always double-check when multiplying or dividing by a negative number.
  • Misinterpreting "Or" and "And": Make sure you understand the difference in how they combine solutions.
  • Incorrectly Graphing: Use open circles for strict inequalities (>, <) and closed circles for inequalities that include equality ( le, ge).

Practice Makes Perfect

Solving compound inequalities might seem tricky at first, but with practice, you'll become a pro! The more you work through different examples, the more comfortable you'll get with the process. Try tackling some similar problems on your own, and don't be afraid to make mistakes – that's how we learn! Remember to break down the problem, solve each inequality separately, and then carefully combine the solutions based on whether it's an "or" or an "and" statement. And most importantly, have fun with it!