Last Digit Of 1x3x5x...x71: Math Problem Solution

by SLV Team 50 views

Hey guys! Today, we're diving into a cool math problem where we need to figure out the last digit of the product P, which is calculated by multiplying all the odd numbers from 1 up to 71. It might sound intimidating at first, but trust me, we can break it down and solve it together. So, let's get started and explore how to find that final digit!

Understanding the Problem

So, the main keyword here is understanding the product P = 1 x 3 x 5 x ... x 71. What this means is that we're multiplying all the odd numbers starting from 1 and going all the way up to 71. The challenge is not to calculate the entire product (because that would be a massive number!), but to find the last digit of that product. This is a classic number theory problem, and the key to solving it lies in observing patterns and understanding how multiplication affects the last digit of a number. When we talk about the last digit, we're essentially looking at the units place. Think about it: when you multiply numbers, the last digit of the result is determined only by the last digits of the numbers you're multiplying. For instance, if you multiply 23 by 47, the last digit of the result will be the same as the last digit of 3 multiplied by 7, which is 1. This principle will be crucial in simplifying our calculation. Now, let's dive deeper into how we can use this to our advantage.

We need to identify if there's a specific odd number within our product that can greatly influence the final digit. Think about the number 5. What happens when you multiply any odd number by 5? The result will always end in either 5 or 0. This is a crucial observation because once we encounter a 5 in our product, the last digit will either remain 5 or become 0. Since all the numbers we are multiplying are odd, the final digit cannot be 0 (an even number). Therefore, the presence of 5 in our product guarantees that the last digit will be 5. This drastically simplifies our problem. We don't need to calculate the entire product; we just need to recognize that 5 is one of the factors.

Breaking Down the Calculation

Alright, let's break down this calculation step by step, guys. We know our product P looks like this: P = 1 x 3 x 5 x 7 x 9 x ... x 71. Notice anything significant? Yep, the number 5 is right there in the sequence! This is a key observation. As we discussed earlier, multiplying any odd number by 5 results in a number ending in 5. So, let's see what happens when we start multiplying these odd numbers together:

  • 1 x 3 = 3
  • 3 x 5 = 15

See that? We've already got a number ending in 5. Now, let's keep going:

  • 15 x 7 = 105

Still ending in 5! This pattern will continue because we are only multiplying by odd numbers. Think about it – any number ending in 5, when multiplied by an odd number, will always result in a number ending in 5. For example:

  • 105 x 9 = 945
  • 945 x 11 = 10395

And so on. It doesn't matter which odd number we multiply; the last digit will stubbornly remain 5. This is the beauty of this problem – once you spot the 5, the rest becomes much easier. We don't need to compute the entire product to figure out the last digit. We just need to recognize this pattern. So, armed with this knowledge, what can we confidently say about the last digit of P?

The Decisive Role of 5

Let's emphasize the decisive role of the number 5 in determining the last digit. The number 5 is a game-changer in multiplication, especially when dealing with odd numbers. When you multiply 5 by any odd number, the result always ends in 5. This is because 5 multiplied by an odd number can be represented as 5 * (2n + 1), where n is any integer. This simplifies to 10n + 5, and any number in the form 10n + 5 will always have 5 as its last digit. This simple algebraic understanding reinforces our observation and gives us a solid foundation for our solution.

Now, consider our product P. It includes 5 as one of its factors. This means that regardless of the other numbers we multiply, the presence of 5 guarantees that the final result will end in either 0 or 5. However, we are only multiplying odd numbers. If there were an even number in the product, the last digit could potentially be 0. But since we're dealing exclusively with odd numbers, the last digit cannot be 0. This is because multiplying any number ending in 5 by an odd number will always yield a number ending in 5. Therefore, the presence of 5, combined with the fact that all other factors are odd, decisively determines the last digit of the product P.

Final Answer

Okay, guys, we've reached the final stretch! After breaking down the problem and understanding the pattern, especially the crucial role of the number 5, we can confidently determine the last digit of the product P = 1 x 3 x 5 x ... x 71. We saw how multiplying any odd number by 5 results in a number ending in 5, and since all the numbers in our product are odd, this pattern will hold true throughout the calculation.

Therefore, the last digit of the product P is 5. Isn't that neat? We didn't have to do a massive calculation to arrive at the answer. By understanding the properties of numbers and spotting the key element (in this case, the number 5), we solved the problem efficiently. Math is full of these cool tricks and patterns, and it's always fun to uncover them. So, keep exploring and keep learning!

Conclusion

To wrap things up, guys, remember the key takeaways from this problem. Firstly, understanding the question and identifying the core concept is crucial. In this case, it was recognizing that we only needed to find the last digit, not the entire product. Secondly, spotting patterns can significantly simplify complex problems. The presence of 5 in the product was the game-changer. Lastly, don't be afraid to break down the problem into smaller, manageable steps. This makes the solution process less daunting and more intuitive.

I hope you enjoyed working through this problem with me! Keep practicing and exploring different mathematical concepts. You'll be amazed at the patterns and relationships you discover. Until next time, keep those math muscles flexed!